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ΔS_sur for H₂+1/2O₂ $\to$ H₂O, ΔH= - 280 KJ at 400 K is

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700 J/g / K

700 KJ / mol / K

700 J/mol/K

0.7 J / mol / K

answer is C.

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Detailed Solution

begin{array}{l} Delta {S_{Surr.}} = - Delta {S_{sys}}\\ Delta {S_{Surr.}}, = - left( {frac{{Delta {H_{sys}}}}{T}} right) = - left( {frac{{ - 280 times 1000}}{{400}}} right)\\ ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, = ,700J/mole/K end{array}

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