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Cell A has emf 2E and internal resistance 4r. Cell B has emf E and internal resistance r. The negative of A is connected to the positive of B and a load resistance of R is connected across the battery formed. If the terminal potential difference across A is zero, then R is equal to

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answer is C.

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Detailed Solution

$i = \frac{e_{1} + e_{2}}{R + r_{1} + r_{2}}, V_{1} = E_{1} - {ir}_{1} = 0$

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