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Q.

Center of mass of a system of particles is given by the formula.

m1x1+m2x2+m3x3+.....m1+m2+m3+....

where m1, m2 ... are their masses and x1, x2,... are their x coordinates

then if 1kg, 2kg, 3kg, ..........49kg are at 1cm, 2cm, 3cm, ....49 cm their center of mass is at

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a

37.66 cm

b

23 cm 

c

33 cm

d

24.5 cm

answer is A.

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Detailed Solution

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According to the formula here position of COM is 

xcm= 1×1+2×2+...+n×n..1+2+3+...+n=nn+12n+16 nn+112 =2n+13 here n=49  xcm=33 cm

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