Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

It will not prefer to undergo redox reactions.

It will prefer to gain electron and act as an oxidizing agent

It acts as both, oxidizing and reducing agent.

It will prefer to give away an electron and behave as reducing agent

answer is B.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Cerium exists in two different oxidation state +3, +4

$\begin{array}{ll} {Ce}^{+ 4} + e^{-} \to {Ce}^{3 +} & E^{0} = + 1.61 V \\ {Ce}^{+ 3} + 3 e^{-} \to Ce & E^{0} = - 2.336 V \end{array}$

It shows Ce⁺⁴ acts as a strong oxidising agent & accepts electron.

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test