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${CH}_{2} = {CH}_{2} + O_{2} \overset{One step oxidation, metal ion}{\to} {CH}_{3} CHO (90 % y i e l d)$
Oxidation states of metal ions used

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+2, +2

+2, +4

+2, -3

-2, -3

answer is B.

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Detailed Solution

Given, Chemical reaction

${CH}_{2} = {CH}_{2} + O_{2} \overset{One step oxidation, metal ion}{\to} {CH}_{3} CHO (90 % y i e l d)$

The oxidation state of Pd is +2.

The oxidation state of Cu is +2.

So, the oxidation state of metal ions is +2, +2.

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