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${CH}_{2} = CH - COOH \overset{{LiAlH}_{4}}{\to} X .$ The product x is

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CH₃ CH₂ COOH

CH₃ CH₂ CH₂ OH

CH₃ CH₂ CHO

CH₂ = CH – CH₂ – OH

answer is C.

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Detailed Solution

LiAlH₄ is a versatile reducing which can reduce carbonyl group but not -C=C- bond.

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