$C + H_{2} O \to CO + H_{2}$ . Here, $H_{2} O$ acts as

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Oxidizing agent

Reducing agent

(A) and (B) both

None of these

answer is A.

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Detailed Solution

$C \to CO$ , carbon gets oxidized to carbon monoxide in the presence of water (oxidation number changes from $O$ to $+ 2$ ). That is, $H_{2} O$ acts as an oxidizing agent in this reaction.

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