CH3−C|CH3|CH3−Br+CH3ONa→P+QIn this reaction P and Q are (mainly)

C H 3 − C | C H 3 = C H 2 + C H 3 O H

CH3−C|CH3|CH3−Br+CH3ONa→P+QIn this reaction P and Q are (mainly)

C H 3 − C | C H 3 = C H 2 + C H 3 O H

C H 3 − C | C H 3 | C H 3 − O − C H 3 + C H 3 O H

C H 3 − C H | O C H 3 − C H 3 + C H 3 O H

C H 3 − C | C H 3 = C H 2 + C H 3 O H

C H 3 − C H | C H 3 − O C H 3 + C H 3 O H

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${CH}_{3} - C_{\underset{{CH}_{3}}{|}}^{\overset{{CH}_{3}}{|}} - Br + {CH}_{3} ONa \to P + Q$
In this reaction P and Q are (mainly)

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$C H_{3} - C_{\underset{C H_{3}}{|}}^{\overset{C H_{3}}{|}} - O - C H_{3} + C H_{3} O H$

$C H_{3} - {C H}_{\underset{O C H_{3}}{|}}^{} - C H_{3} + C H_{3} O H$

$C H_{3} - C_{\underset{C H_{3}}{|}}^{} = C H_{2} + C H_{3} O H$

$C H_{3} - {C H}_{\underset{C H_{3}}{|}}^{} - O C H_{3} + C H_{3} O H$

answer is C.

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Detailed Solution

Tertiary butyl bromide react with sodium Methoxide and gives isobutylene

$C H_{3} - C_{\underset{C H_{3}}{|}}^{\overset{C H_{3}}{|}} - B r + N a O C H_{3} \to C H_{3} - C_{\underset{C H_{2}}{| |}}^{\overset{C H_{3}}{|}} + C H_{3} O H$

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CH3−C|CH3|CH3−Br+CH3ONa→P+QIn this reaction P and Q are (mainly)

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CH3−C|CH3|CH3−Br+NaOCH3→CH3−C||CH2|CH3+CH3OH

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${CH}_{3} - C_{\underset{{CH}_{3}}{|}}^{\overset{{CH}_{3}}{|}} - Br + {CH}_{3} ONa \to P + Q$
In this reaction P and Q are (mainly)

$C H_{3} - C_{\underset{C H_{3}}{|}}^{\overset{C H_{3}}{|}} - B r + N a O C H_{3} \to C H_{3} - C_{\underset{C H_{2}}{| |}}^{\overset{C H_{3}}{|}} + C H_{3} O H$