Q.

CH3CH=CHOCH2CH3dilacidX+Y

(Y gives positive haloform test) The number of possible isomers for X excluding stereo isomers and including X.

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answer is 9.

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Detailed Solution

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CH3CH=CHOH,  

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,HOCH2CH=CH2, CH3CH2CHO

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CH3OCH=CH2

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CH3−CH=CH−O−CH2−CH3→dil acidX+Y(Y gives positive haloform test) The number of possible isomers for X excluding stereo isomers and including X.