CH3−CH=CH2→ CH3−C≡CH The correct sequence of reagents involved is

CH3−CH=CH2→CCl4Br2 CH3−CH(Br)−CH2Br→b)NaNH2/Δa)alc.KOH/ΔCH3−C≡CH

CH3−CH=CH2→ CH3−C≡CH The correct sequence of reagents involved is

CH3−CH=CH2→CCl4Br2 CH3−CH(Br)−CH2Br→b)NaNH2/Δa)alc.KOH/ΔCH3−C≡CH

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$C H_{3} - C H = C H_{2} \overset{}{\to} C H_{3} - C \equiv C H$ The correct sequence of reagents involved is

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$H B r, N a N H_{2} / Δ, a l c . K O H / Δ$

$H B r, a l c . K O H / Δ$

$B r_{2} / C C l_{4}, a l c . K O H / Δ, N a N H_{2} / Δ$

$B r_{2} / C C l_{4}, a l c . K O H / Δ, H_{3} O^{+}$

answer is C.

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Detailed Solution

$C H_{3} - C H = C H_{2} \to_{C C l_{4}}^{B r_{2}}$

$C H_{3} - C H (B r) - C H_{2} B r \to_{b) N a N H_{2} / Δ}^{a) a l c . K O H / Δ} C H_{3} - C \equiv C H$

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CH3−CH=CH2→ CH3−C≡CH The correct sequence of reagents involved is

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$C H_{3} - C H = C H_{2} \overset{}{\to} C H_{3} - C \equiv C H$ The correct sequence of reagents involved is