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${CH}_{3} - C H_{2} - B r$ on treatment with ${LiAH}_{4}$ gives ethane gas ${(C H_{3})}_{3} C - B r$ on same treatment gives H₂ gas because

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The former is ${SN}_{2}$ and later is $E_{2}$ reaction

The former is $E_{2}$ and later is ${SN}_{2}$ reaction

The former is ${SN}_{1}$ and later is $E_{2}$ reaction

The former is $E_{2}$ and later is ${SN}_{1}$ reaction

answer is A.

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