$C H_{3} - C H_{2} - \overset{\overset{O}{| |}}{C} - C H O \overset{N a B H_{4}}{\to}$ product(s) in the above reaction is

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$C H_{3} C H_{2} C H (O H) C H_{2} O H$

$C H_{3} C H_{2} C O O H + C O_{2}$

$C H_{3} C H_{2} C O C H_{2} O H$

$C H_{3} C H_{2} C H (O H) C H O$

answer is A.

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Detailed Solution

$C H_{3} - C H_{2} - \overset{\overset{O}{| |}}{C} - C H O \overset{N a B H_{4}}{\to} C H_{3} - C H_{2} - \overset{\overset{O H}{|}}{C H} - C H_{2} O H$

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