CH3-CH2-CO-NH2→NaOH/Br2AAqueous solution of A.

A will turn red litmus to blue as the A formed by the series of given reactions will be basic. If a basic compound is tested with litmus, it turns red litmus blue and if an acidic compound is tested with litmus, it turns blue litmus red. No change is observed in the case of a neutral compound. The A formed here is CH3-CH2-NH2, which is basic. Thus, red litmus will turn blue.Hence, the correct answer is option B) Turns red litmus to blue.

CH3-CH2-CO-NH2→NaOH/Br2AAqueous solution of A.

A will turn red litmus to blue as the A formed by the series of given reactions will be basic. If a basic compound is tested with litmus, it turns red litmus blue and if an acidic compound is tested with litmus, it turns blue litmus red. No change is observed in the case of a neutral compound. The A formed here is CH3-CH2-NH2, which is basic. Thus, red litmus will turn blue.Hence, the correct answer is option B) Turns red litmus to blue.

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${CH}_{3} - {CH}_{2} - CO - {NH}_{2} \overset{NaOH / {Br}_{2}}{\to} A$
Aqueous solution of $A$ .

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Turns red litmus to blue

Does not affect the litmus

Turns blue litmus to red

Decolourise the litmus

answer is B.

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Detailed Solution

A will turn red litmus to blue as the A formed by the series of given reactions will be basic.
If a basic compound is tested with litmus, it turns red litmus blue and
if an acidic compound is tested with litmus, it turns blue litmus red.
No change is observed in the case of a neutral compound. The A formed here is ${CH}_{3} - {CH}_{2} - {NH}_{2}$ , which is basic. Thus, red litmus will turn blue.

Hence, the correct answer is option B) Turns red litmus to blue.

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