${\mathrm{CH}}_3-{\mathrm{CH}}_2\mathrm{OH}\stackrel{\mathrm{Con} {\mathrm{H}}_2\mathrm{SO}4}{\to }?$

The product of the reaction is.

Answer: A

Heating ethanol at 443 K with excess concentrated sulphuric acid results in the dehydration of ethanol to give ethene.

${\mathrm{CH}}_3-{\mathrm{CH}}_2\mathrm{OH}\stackrel{\mathrm{Hot}.\mathrm{Con} {\mathrm{H}}_2{\mathrm{SO}}_4}{\to }{\mathrm{CH}}_2={\mathrm{CH}}_2+{\mathrm{H}}_2\mathrm{O}$

The concentrated sulphuric acid act as a dehydrating agent which removes water from ethanol.