${\mathrm{CH}}_3-\stackrel{\underset{\left|\right|}{\mathrm{O}}}{\mathrm{C}}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_3\stackrel{{\mathrm{KMnO}}_4/{\mathrm{H}}^{+}}{\to }\mathrm{X}.$ X in the reaction is/are

On heating with strong oxidant like KMnO₄ / H⁺ ketones undergo C-C cleavage to give lower carboxylic acids.

According to popoff's rule during the strong oxidation of ketones, C-C cleavage occurs such a way that the keto group always goes with small alkyl group. So the major products are obtained in possibility-I