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CH3−COOH→Br2/P(A)→NaCN(B)→HOH/H+(C). The product (C) will be

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CH3−COOH→Br2/P(A)→NaCN(B)→HOH/H+(C). The product (C) will be

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$C H_{3} - C O O H \overset{B r_{2} / P}{\to} (A) \overset{N a C N}{\to} (B) \overset{H O H / H^{+}}{\to} (C) .$ The product (C) will be