(CH3)3CBr →r1H2O(CH3)3C I→r2H2O(CH3)3C Cl→r3H2Or1,r2,and r3 are rate of reactions respectively then correct relation between them is

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${({CH}_{3})}_{3} CBr \to_{r_{1}}^{H_{2} O}$
${({CH}_{3})}_{3} C I \to_{r_{2}}^{H_{2} O}$
${({CH}_{3})}_{3} C Cl \to_{r_{3}}^{H_{2} O}$
r₁,r₂,and r₃ are rate of reactions respectively then correct relation between them is

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r₁=r₂=r₃

r₁> r₂>r₃

r₁< r₂< r₃

r₂ > r₁ >r₃

answer is D.

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rate of S_N reaction $\infty$ leaving ability of leaving group

leaving ability I^->Br^->Cl^-

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