${({CH}_{3})}_{3} {CH}_{2} {CH}_{2}^{+}$ rearranges to most stable carbocation in two steps. The sequence of rearrangement involves

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In both steps hydride shift

In both steps alkyl shift

Hydride shift followed by methyl shift

Methyl shift followed by hydride shift

answer is B.

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Detailed Solution

(CH₃)CH₂C $H_{2}^{+}$ $\overset{Hydride shift}{\to}$ (CH₃)₃ $\overset{+}{CH}$ CH₃ $\overset{{CH}_{3}^{-} shift}{\to}$ (CH₃)₂ $\overset{+}{C}$ CH(CH₃)₂

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