${\mathrm{CH}}_3\mathrm{Br}+{\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Br}\stackrel{\mathrm{Na}/\mathrm{dry}.\mathrm{either}}{\to }\text{ product. }$Possible products in the above reaction

$\begin{array}{l}{}^{\bullet }\mathrm{CH}_3+{}^{\bullet }\mathrm{CH}_3\to {\mathrm{C}}_2{\mathrm{H}}_6\\ {}^{\bullet }\mathrm{CH}_3+{\mathrm{CH}}_3\mathrm{C}{{\mathrm{H}}_2}^{\bullet } \to {\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_3\\ 2{\mathrm{CH}}_3{{\mathrm{CH}}_2}^{\bullet }\to {\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{CH}}_3\\ {\mathrm{CH}}_3-\mathrm{C}{{\mathrm{H}}_2}^{\bullet }\to {\mathrm{CH}}_2={\mathrm{CH}}_2\\ {}^{\bullet }\mathrm{CH}_3+{\mathrm{H}}^{\bullet }\to {\mathrm{CH}}_4\end{array}$