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Q.

CH3BretherMgA CdCl2B CH3CH2CH2COCl; the compound ‘C’ in the reaction is

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a

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b

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c

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d

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answer is B.

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Detailed Solution

A  is  CH3MgBr; 2CH3MgBr+CdCl2 CH32Cd(B)+2MgBrCl 2CH3CH2CH2COCl+CH32Cd CH3CH2CH2COCH3(C)+CdCl2

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