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Q.

${CH}_{3} - {CH}_{2} - C = N \overset{\times}{⟶} {CH}_{3} {CH}_{2} CHO$ . The compound X is

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a

${LiAIH}_{4}$ / ether/ $H_{2} O$

b

${LiAIH}_{4}$ / ether

c

$H_{2} / Pd - {BaSO}_{4}$

d

${SnCl}_{2} / HCl / H_{2} O, boil$

answer is A.

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Detailed Solution

${CH}_{3} - {CH}_{2} - C \equiv N \overset{{SnCl}_{2} / HCl}{\to} {CH}_{3} {CH}_{2} CH = NH \to_{boil}^{H_{2} O} {CH}_{3} {CH}_{2} CHO + {NH}_{4} Cl$

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