CH3CH2CH = CHCH3 + O3 →ZnH2O

The ozonolysis of alkenes produces ozonide as intermediate which undergo hydrolysis and forms corresponding carbonyl compounds. The breakage of double bond takes place and forms carbonyls with broken fragment having same number of carbon atoms. 2-pentene undergo ozonolysis produces CH3CH2CHO and CH3CHO each one mole

CH3CH2CH = CHCH3 + O3 →ZnH2O

The ozonolysis of alkenes produces ozonide as intermediate which undergo hydrolysis and forms corresponding carbonyl compounds. The breakage of double bond takes place and forms carbonyls with broken fragment having same number of carbon atoms. 2-pentene undergo ozonolysis produces CH3CH2CHO and CH3CHO each one mole

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${CH}_{3} {CH}_{2} CH = {CHCH}_{3} + O_{3} \to_{Zn}^{H_{2} O}$

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${CH}_{3} {CH}_{2} CHO & {CH}_{3} CHO; each one mole$

$Two moles of {CH}_{3} {CH}_{2} CHO$

$Two moles of {CH}_{3} CHO$

${CH}_{3} - {CH}_{2} - CH - CH - {CH}_{3}$

answer is A.

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Detailed Solution

The ozonolysis of alkenes produces ozonide as intermediate which undergo hydrolysis and forms corresponding carbonyl compounds.
The breakage of double bond takes place and forms carbonyls with broken fragment having same number of carbon atoms.
2-pentene undergo ozonolysis produces ${CH}_{3} {CH}_{2} CHO and {CH}_{3} CHO$ each one mole