CH3CH2CH2I→alc.KOHA→H+,H2OB→SOCl2C→ LiAlH4D Molecular weight of ‘D’’ is ______

CH3CH2CH2I→alc.KOHCH3CH=CH2→H+,H2O CH3CH(OH)CH3→SOCl2 CH3CH(Cl)CH3→LiAlH4CH3CH2CH3

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${CH}_{3} {CH}_{2} {CH}_{2} I \overset{alc . KOH}{\to} A \overset{H^{+}, H_{2} O}{\to} B \overset{{SOCl}_{2}}{\to} C \overset{{LiAlH}_{4}}{\to} D$ Molecular weight of ‘D’’ is ______

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answer is 44.

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Detailed Solution

${CH}_{3} {CH}_{2} {CH}_{2} I \overset{alc . KOH}{\to} C H_{3} CH = C H_{2} \overset{H^{+}, H_{2} O}{\to} {CH}_{3} CH (O H) {CH}_{3} \overset{S O C l_{2}}{\to} C H_{3} C H (C l) C H_{3} \overset{L i A l H_{4}}{\to} C H_{3} C H_{2} C H_{3}$

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