$C H_{3} {CH}_{2} Cl \overset{alc . KCN}{\to} A (major)$ correct statements are (B is the minor product)
A) A on hydrolysis given propanoic acid
B) A on partial hydrolysis gives propanamide
C) A on reduction with ${LiACH}_{4}$ (or) $Na / C_{2} H_{5} OH$ (or) $H_{2} / Pt$ gives 1-propanamine
D) B in presence of $NaHg / C_{2} H_{5} OH$ (or) $H_{2} / Cal$ gives N-methyl Ethanamine
E) B on hydrolysis gives Ethanamine and methanoic acid
F) A and B are functional isomers

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All are correct

A, B, D, E, F only

A, C, D, E only

A, B, C, D, E only

answer is A.

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Detailed Solution

$\begin{array}{l} {CH}_{3} {CH}_{2} CN - major \\ {CH}_{3} {CH}_{2} NC - minor \end{array}$

ionic Cu acids like KCN & NaCN with RX gives RCN on major produce

$\underset{(A)}{{CH}_{3} {CH}_{2} CN} \to_{H^{+} or {OH}^{-}}^{H_{2} O} \underset{Amide}{{CH}_{3} {CH}_{2} {CONH}_{2}} \to_{H^{+} (or) {OH}^{-}}^{H_{2} O} \underset{Carboxylic acid}{{CH}_{3} {CH}_{2} COOH}$

$\underset{(A)}{{CH}_{3} {CH}_{2} C} \equiv N + 4 (H) \to_{Na - C_{2} H_{5} OH}^{{LiACH}_{4} (or)} {CH}_{3} {CH}_{2} {CH}_{2} {NH}_{2}$

$\underset{}{\underset{(B)}{{CH}_{3} {CH}_{2} N} \underline{\underline{\to}} C + (H) \to_{(or) H_{2} / cat}^{NaHg / C_{2} H_{5} OH} {CH}_{3} {CH}_{2} {NHCH}_{3}}$