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Q.

${CH}_{3} {CH}_{2} Cl + {LiAlH}_{4} \to {CH}_{3} {CH}_{3}$
This reduction process follows:

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a

$S_{N} 1$ mechanism

b

$E_{1}$ mechanism

c

$S_{N} 2$ mechanism

d

$E_{2} mechanism$

answer is B.

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Detailed Solution

Lithium aluminium hydride contains hydride $H^{-}$ which substitute halide

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