${CH}_{3} {CH}_{2} COOH \underset{Red-P}{\overset{{Cl}_{2}}{\to}} A \overset{Alc . KOH}{\to} B$ What is B?

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CH 3 CH 2 COCl

CH 3 CH 2 CHO

CH 2 = CHCOOH

CH 2 CH 2 COOH

answer is C.

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Detailed Solution

${CH}_{3} {CH}_{2} COOH \underset{Red-P}{\overset{{Cl}_{2}}{\to}} {CH}_{3} CHClCOOH \overset{A l c K O H}{\to} \underset{Acrylic acid}{C H_{2} = C H - C O O H}$

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