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Q.

${CH}_{3} {CH}_{2} COONa \overset{NaOH + CaO / ∆}{\to} P (organic compound); {CH}_{3} COONa (aq) \overset{electrolysis}{\to} Q (organic compound);$
The compounds P and Q are

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a

Homologues

b

Unsaturated hydrocarbons

c

Same compounds

d

Positional isomers

answer is C.

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Detailed Solution

${CH}_{3} {CH}_{2} COONa + NaOH \overset{CaO / ∆}{\to} {CH}_{3} - {CH}_{3} (P) + {Na}_{2} {CO}_{3};$

$2 {CH}_{3} COONa + 2 H_{2} O \overset{electrolysis}{\to} {CH}_{3} - {CH}_{3} (Q) + 2 {CO}_{2} + 2 NaOH + H_{2}$

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CH3CH2COONa→NaOH+CaO/∆ P(organic compound); CH3COONaaq→electrolysis Q(organic compound); The compounds P and Q are