${CH}_{3} {CH}_{2} {NH}_{2}$ contains a basic ${NH}_{2}$ group, but ${CH}_{3} {CONH}_{2}$ does not, because.

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In ${CH}_{3} {CH}_{2} {NH}_{2}$ there is no resonance, while in acetamide the lone pair of electron on $N$ -atom is delocalized and therefore less available for protonation

In ${CH}_{3} {CH}_{2} {NH}_{2}$ the electron pair on $N$ -atom is delocalized by resonance

None of these

Acetamide is amphoteric in character

answer is C.

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Detailed Solution

${CH}_{3} - {CH}_{2} - {NH}_{2}$ is the chemical formula of ethyl amine and ${CH}_{3} {CONH}_{2}$ is the chemical formula of acetamide. In acetamide, the ${CH}_{3}$ group attached to the $C = O$ shows inductive effect and it undergoes resonance hence increasing its stability which does not happen in the case of ethyl amine. Due to resonance, less number of electrons are available for donation so, it is less basic than ethylamine.