${CH}_{3} {CH}_{2} OH \underset{step-1}{\overset{{Cl}_{2}}{⟶}} {CH}_{3} CHO \frac{3 {Cl}_{2}}{step-2} {Cl}_{3} CCHO .$
In the above reaction, the role of $C l_{2}$ in step-1 and step-2 respectively.

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Oxidation and chlorination

Reduction and substitution

Reduction and chlorination

Oxidation and addition

answer is A.

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Detailed Solution

Given data : It is given to identify the role of Chlorine in the below chemical reaction.

Explanation

${CH}_{3} {CH}_{2} OH \underset{step-1}{\overset{{Cl}_{2}}{⟶}} {CH}_{3} CHO \frac{3 {Cl}_{2}}{step-2} {Cl}_{3} CCHO .$
As we know $C H_{3} C H_{2} O H$ is an Alcohol, and it is converted to $C H_{3} C H O$ , which is an aldehyde, and we know that the conversion of alcohol to aldehyde is oxidation. Conversion of $C H_{3} C H O$ (Aldehyde) to $C l_{3} C C H O$ Is chlorination because $3 H$ is replaced by Cl.