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${CH}_{3} {CH}_{2} OH \frac{{Cl}_{2}}{step - 1} ⟶ {CH}_{3} CHO \frac{3 {Cl}_{2}}{step-2} \to$ Cl₃CCHO. In the above reaction, the role
of Cl₂ in step-1 and step-2 respectively

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An Intiative by Sri Chaitanya

Oxidation and chlorination

Reduction and chlorination

Oxidation and addition

Reduction and substitution

answer is A.

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Detailed Solution

Since loss of hydrogen in step-1 it is Oxidation . However step -II Involves replacement of by Cl, we can say that it is chlorination reaction.

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