${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH} \stackrel{\mathrm{Con} {\mathrm{H}}_2\mathrm{SO}4}{\to }?$

The product of the reaction is __________.

Heating ethanol at 443 K with excess concentrated sulphuric acid results in the dehydration of ethanol to give ethene.

${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH} \stackrel{\mathrm{Hot}.\mathrm{Con} {\mathrm{H}}_2{\mathrm{SO}}_4}{\to } {\mathrm{CH}}_2={\mathrm{CH}}_2 + {\mathrm{H}}_2\mathrm{O}$

The concentrated sulphuric acid act as a dehydrating agent which removes water from ethanol.