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Q.

CH3−CH=CH−CH3⟶X product is Y (nonresolvable). Then X can be

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a

Bromine water

b

HCO3H followed by H3O+

c

Cold alkaline KMnO4

d

All of the above

answer is C.

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Detailed Solution

Alkene reacts with cold KMnO4 and forms diol. Here, the sp2 hybridized carbon atom changes to sp3 hybridized because 2 -OH group attaches to it. Compound forms is a meso compound as shown below.

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CH3−CH=CH−CH3⟶X product is Y (nonresolvable). Then X can be