CH3−CH=CH−CH3⟶X product is Y (nonresolvable). Then X can be

Alkene reacts with cold KMnO4 and forms diol. Here, the sp2 hybridized carbon atom changes to sp3 hybridized because 2 -OH group attaches to it. Compound forms is a meso compound as shown below.

CH3−CH=CH−CH3⟶X product is Y (nonresolvable). Then X can be

Alkene reacts with cold KMnO4 and forms diol. Here, the sp2 hybridized carbon atom changes to sp3 hybridized because 2 -OH group attaches to it. Compound forms is a meso compound as shown below.

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

${CH}_{3} - CH = CH - {CH}_{3} \overset{X}{⟶} product is Y$ (nonresolvable). Then X can be

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

Bromine water

HCO₃H followed by H₃O⁺

Cold alkaline KMnO₄

All of the above

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Alkene reacts with cold KMnO₄ and forms diol. Here, the sp² hybridized carbon atom changes to sp³ hybridized because 2 -OH group attaches to it. Compound forms is a meso compound as shown below.