${CH}_{3} - CH = CH - {CH}_{3} \overset{X}{⟶} product is Y$ (nonresolvable). Then X can be

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Bromine water

HCO₃H followed by H₃O⁺

Cold alkaline KMnO₄

All of the above

answer is C.

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Detailed Solution

Alkene reacts with cold KMnO₄ and forms diol. Here, the sp² hybridized carbon atom changes to sp³ hybridized because 2 -OH group attaches to it. Compound forms is a meso compound as shown below.

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