$C H_{3} C H O$ and $C_{6} H_{5} C H O$ can be distinguished by

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Tollens’ reagent

Baeyer's reagent

$I_{2} + N a O H$

Schiff's reagent

answer is D.

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Detailed Solution

Acetaldehyde reacts with iodoform ( $I_{2} + N a O H$ ) which gives white crystals of iodoform and Benzaldehyde does not show reactivity towards iodoform. Whereas acetaldehyde and benzaldehyde both react with Baeyer's, Tollens', Schiff's reagent.

$C H_{3} C H O + 3 I_{2} + 4 N a O H \to C H I_{3} + H C O O N a + 3 N a I + 3 H_{2} O$ and

$C_{6} H_{5} C H O + I_{2} + 4 N a O H \to$ No Reaction

Hence, the correct answer is option (D) $I_{2} + N a O H$ .

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