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Q.

${CH}_{3} CHO + HCHO \to_{Heat}^{dil NaOH} A \to_{H_{3} O^{+}}^{HCN} B$ .
The structure of the compound (B) is

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a

${CH}_{2} = CH (CN) CHCOOH$

b

${CH}_{3} CH = CHCH (OH) COOH$

c

${CH}_{3} CH (OH) COOH$

d

${CH}_{2} = CHCH (OH) COOH$

answer is A.

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Acetaldehyde undergoes aldol condensation as it has alpha carbon hydrogen

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CH3CHO + HCHO →Heatdil NaOH A →H3O+HCN B.The structure of the compound (B) is