CH3Cl→KCNA→H+ / H2OB→NH3C→ΔD. The compound ‘D’ is

A = CH3 – CN B = CH3COOHC = CH3COONH4+

CH3Cl→KCNA→H+ / H2OB→NH3C→ΔD. The compound ‘D’ is

A = CH3 – CN B = CH3COOHC = CH3COONH4+

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$C H_{3} C l \overset{K C N}{\to} A \overset{H^{+} / H_{2} O}{\to} B \overset{N H_{3}}{\to} C \overset{Δ}{\to} D$ . The compound ‘D’ is

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CH₃-CN

CH₃ – CONH₂

CH₃ - CH₂ – CN

C₂H₅ – CONH₂

answer is B.

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Detailed Solution

A = CH₃ – CN
B = CH₃COOH
C = ${CH}_{3} {COONH}_{4}^{+}$

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CH3Cl→KCNA→H+ / H2OB→NH3C→ΔD. The compound ‘D’ is

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$C H_{3} C l \overset{K C N}{\to} A \overset{H^{+} / H_{2} O}{\to} B \overset{N H_{3}}{\to} C \overset{Δ}{\to} D$ . The compound ‘D’ is