CH3COOH→1 mole Cl2/ Red PA→KCNB→H+/H2O Hence compound ‘C’ is

The compound 'C' formed in the given reaction is:Malonic acidDetailed Explanation:Starting with acetic acid (CH₃COOH), it reacts with chlorine (Cl₂) in the presence of red phosphorus (Red P) to form chloroacetic acid (CH₂ClCOOH).The chloroacetic acid then reacts with KCN (potassium cyanide) to undergo nucleophilic substitution, replacing the chlorine atom with a cyano group, resulting in cyanoacetic acid (CH₂(CN)COOH).Finally, cyanoacetic acid undergoes hydrolysis (with H+/H₂O), which converts the cyano group (-CN) into a carboxyl group (-COOH), forming malonic acid (CH₂(CO₂H)₂).Thus, the compound 'C' is malonic acid (CH₂(CO₂H)₂).Concept:Malonic acid is a dicarboxylic acid with two carboxyl groups (-COOH) attached to a central carbon atom.The given reactions outline a typical method of synthesizing malonic acid starting from acetic acid through a series of halogenation, nucleophilic substitution, and hydrolysis reactions.

CH3COOH→1 mole Cl2/ Red PA→KCNB→H+/H2O Hence compound ‘C’ is

The compound 'C' formed in the given reaction is:Malonic acidDetailed Explanation:Starting with acetic acid (CH₃COOH), it reacts with chlorine (Cl₂) in the presence of red phosphorus (Red P) to form chloroacetic acid (CH₂ClCOOH).The chloroacetic acid then reacts with KCN (potassium cyanide) to undergo nucleophilic substitution, replacing the chlorine atom with a cyano group, resulting in cyanoacetic acid (CH₂(CN)COOH).Finally, cyanoacetic acid undergoes hydrolysis (with H+/H₂O), which converts the cyano group (-CN) into a carboxyl group (-COOH), forming malonic acid (CH₂(CO₂H)₂).Thus, the compound 'C' is malonic acid (CH₂(CO₂H)₂).Concept:Malonic acid is a dicarboxylic acid with two carboxyl groups (-COOH) attached to a central carbon atom.The given reactions outline a typical method of synthesizing malonic acid starting from acetic acid through a series of halogenation, nucleophilic substitution, and hydrolysis reactions.

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${CH}_{3} COOH \overset{1 mole {Cl}_{2} / Red P}{\to} A \overset{KCN}{\to} B$ $\overset{H^{+} / H_{2} O}{\to}$ Hence compound ‘C’ is

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Malonic acid

Oxalic acid

Fumaric acid

Maleic acid

answer is D.

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Detailed Solution

The compound 'C' formed in the given reaction is:

Malonic acid

Detailed Explanation:

Starting with acetic acid (CH₃COOH), it reacts with chlorine (Cl₂) in the presence of red phosphorus (Red P) to form chloroacetic acid (CH₂ClCOOH).
The chloroacetic acid then reacts with KCN (potassium cyanide) to undergo nucleophilic substitution, replacing the chlorine atom with a cyano group, resulting in cyanoacetic acid (CH₂(CN)COOH).
Finally, cyanoacetic acid undergoes hydrolysis (with H+/H₂O), which converts the cyano group (-CN) into a carboxyl group (-COOH), forming malonic acid (CH₂(CO₂H)₂).
Thus, the compound 'C' is malonic acid (CH₂(CO₂H)₂).

Concept:

Malonic acid is a dicarboxylic acid with two carboxyl groups (-COOH) attached to a central carbon atom.
The given reactions outline a typical method of synthesizing malonic acid starting from acetic acid through a series of halogenation, nucleophilic substitution, and hydrolysis reactions.