CH₃NHCH₃ and (CH₃)₃N can be chemically distinguished by

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Carbylamine test

Benedict test

Hinsberg’s reagent

Lucas test

answer is C.

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Detailed Solution

Hinsberg’s reagnt will not react with 3°- amine but react with 2° - amine giving insoluble compound in NaOH
$\begin{array}{l} R_{2} NH + Cl - {SO}_{2} - Ph \\ R_{2} N - {SO}_{2} - Ph \overset{NaOH}{\to} insoluble \end{array}$

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