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Q.

Change in angular momentum of an electron when it jumps from 4th orbit to 5th orbit in Hydrogen atom is

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a

$\frac{h}{2 π}$

b

$\frac{h}{π}$

c

Zero

d

$\frac{2 h}{π}$

answer is A.

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Detailed Solution

Angular momentum of electron in nth orbit is given by, $L_{n} = n \frac{h}{2 π}$

$L_{6} - L_{5} = (6 - 5) \frac{h}{2 π} = \frac{h}{2 π}$

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