Q.

Charge densities of the four quadrants of the ring are λ, –2λ, –λ and + 2λ respectively. The electric potential at the centre of ring is

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a

zero

b

2λ4πε0

c

5λ4πε0

d

2λ4πε0R

answer is B.

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Detailed Solution

V=14πε0qr=14πε0(2λλ+2λ+λ)πr2r
= zero

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