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Q.

Charge density of the given surface is s. Then electric field strength at the centre (of quarter sphere) is

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a

$\frac{σ}{\sqrt{2} ε_{0}}$

b

$\frac{σ}{2 ε_{0}}$

c

$\frac{σ}{2 \sqrt{2} ε_{0}}$

d

$\frac{σ}{4 \sqrt{2} ε_{0}}$

answer is A.

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Detailed Solution

If one half is remove

$E_{net} = \sqrt{{(\frac{σ}{8 ϵ_{0}})}^{2} + {(\frac{σ}{8 ϵ_{0}})}^{2}} \Rightarrow E_{net} = \frac{σ}{4 \sqrt{2} ϵ_{0}}$

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