Charge present on one gram ion of sulphide ion is equal to

$$\begin{gathered} \mathrm{Sulphide} \mathrm{ion} \mathrm{is} {\mathrm{S}}^{-2} \\ \mathrm{Charge} \mathrm{on} \mathrm{one} \mathrm{sulphide} \mathrm{ion} \mathrm{is} =2\times 1.602\times {10}^{-19 }\mathrm{C} \\ \mathrm{Charge} \mathrm{on} \mathrm{one} \mathrm{gram} \mathrm{ion} \mathrm{of} \mathrm{sulphide} \mathrm{ion} =2\times 1.602\times {10}^{-19}\times 6.023\times {10}^{23 }\mathrm{C} \\ =2\times 96500 \mathrm{C} \end{gathered}$$