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Charge Q is spread uniformly over a circular ring of radius R, which gives electrical potential V₁ at its centre. If an arc of length $\frac{πR}{2}$ is removed from the ring [as shown in figure (ii)] keeping the charge Q on the remaining part. The potential due to the remaining part at the centre is V₂then relation between V₁ and V₂ is

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$V_{1} = V_{2}$

$V_{2} = \frac{V_{1}}{4}$

$V_{1} = \frac{V_{2}}{4}$

$V_{2} = \frac{3 V_{1}}{4}$

answer is C.

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Charge and distance are same

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