Q.

Charge Q is spread uniformly over a circular ring of radius R, which gives electrical potential V1 at its centre. If an arc of length πR2 is removed from the ring [as shown in figure (ii)] keeping the charge Q on the remaining part. The potential due to the remaining part at the centre is V2 then relation between V1 and V2 is

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a

V1=V2

b

V2=V14

c

V1=V24

d

V2=3V14

answer is C.

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