Charges of 5 µC each is placed at the corners of an equilateral triangle of side 10 cm. Then find the force on each charge.

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Charges of 5 µC each is placed at the corners of an equilateral triangle of side 10 cm. Then find the force on each charge.

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39N

22.5N

78N

29N

answer is B.

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Detailed Solution

$F_{r} = \frac{\sqrt{3} {Kq}^{2}}{r^{2}}$

$= \frac{\sqrt{3} x 9 x 10^{9} x {(5 x 10^{- 6})}^{2}}{{(10 x 10^{- 2})}^{2}}$

$= \frac{1.73 x 9 x 25 x 10^{- 3}}{10^{- 2}} = 38.92 = 39 N$

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