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Q.

Charges of $+ \frac{10}{3} \times 10^{- 9} C$ are placed at each of the four corners of a square of side 8cm . The potential at the intersection of the diagonals is

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a

$900 \sqrt{2} v o l t$

b

$150 \sqrt{2} v o l t$

c

$1500 \sqrt{2} v o l t$

d

$900 v o l t$

answer is B.

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Detailed Solution

Potential at the center O

$V = 4 \times \frac{1}{4 π ε_{o}} . \frac{Q}{a / \sqrt{2}}$

Where Q $= \frac{10}{3} \times 10^{- 9} C a n d a = 8 c m = 8 \times 10^{- 2} m$

Question Image

$S o V = 4 \times 9 \times 10^{9} \times \frac{\frac{10}{3} \times 10^{- 9}}{\frac{8 \times 10^{- 2}}{\sqrt{2}}} = 1500 \sqrt{2} v o l t$

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