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Charges +q, -4q and +2q are arranged at the corners of an equilateral triangle of side 0.15m. If q=1 µC, their mutual potential energy is

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0.4J

0.5J

0.6J

0.8J

answer is C.

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Detailed Solution

$U = \frac{1}{4 {πε}_{0}} [\frac{q_{1} q_{2}}{r_{1}} + \frac{q_{2} q_{3}}{r_{2}} + \frac{q_{1} q_{3}}{r_{3}}]$

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