Check the divisibility conditions of 3, 4 for the following numbers.

63712

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not divisible by 3, divisible by 4

divisible by 3, not divisible by 4

not divisible by 3, not divisible by 4

none

answer is A.

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Detailed Solution

We use the divisibility theorem for 3 and 4 to find out if the given numbers are divisible by 3 and 4.
For the divisibility of 3, if the sum of the digits in a number is divisible by 3 then the number itself is divisible by 3.
For the divisibility of 4, we know that if the last two digits i.e. the tenth place and unit place digits together in a number are divisible by 4 then the number itself is divisible by 4.
Now we apply the theorems for the given numbers. We check the numbers’ divisibility for 3 and 4 simultaneously.
For 63712, the digits add up 6+3+7+1+2=19 which is not divisible by 3. So, 63712 is not divisible by 3.
And its last two digits are 12 which is divisible by 4. So, 63712 is divisible by 4.
Hence, option (1) is correct.

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