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Q.

Chemical analysis of a carbon compound gave the following percentage composition by weight of the elements present carbon = 10.06%; Hydrogen = 0.84% ; chlorine = 89.10% Calculate the empirical formula of the compound ?

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Detailed Solution

Element%Atomic Weight%/At.wtSimple ratio
C10.061210.0612=0.840.840.84=1
H0.8410.841=0.840.840.84=1
CI89.1035.589.1035.5=2.512.510.84=3

Empirical formula C1H1Cl3=CHCl3

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