Chlorine is passed into dilute, cold KOH solution. What are the oxidation numbers of chlorine in the products formed?

Chlorine is passed into a dilute, cold KOH solution. The Oxidation number of the products are

$\frac{C{l_2}^{ }}{Chlorine}\underset{solution}{\overset{Cold KOH}{\to }}\frac{OC{l}^{-}}{+1} + \frac{C{l}^{-}}{-1}$

Hence, the oxidation states of the products are +1 and -1.