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Chlorine on reaction with iodate ion in basic medium , according to the given equation :
$I O_{3}^{-} + x O H^{-} + C l_{2} \to (A) + y H_{2} O + z C l^{-}$ [ x, y, z are stoichiometric coefficients in balance equations] Compound (A) on heating in acidic medium undergoes,
$(A) \to_{- 4 H_{2} O}^{100^{0} C} (B) \overset{200^{0} C}{\to}$
Identify the compound (C)?

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$I_{2} O_{3}$

$I_{2}$

$I_{2} O_{7}$

$I_{2} O_{5}$

answer is D.

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Detailed Solution

$x = 6, y = 3, z = 2$

${IO}_{3}^{-} + 6 {OH}^{-} + {Cl}_{2} \to {OO}_{6}^{5 -} + 3 H_{2} O + 2 {Cl}^{-} \Rightarrow I O_{6}^{5} \overset{H^{+}}{\to} H_{5} {IO}_{6} \Rightarrow 2 H_{5} I O_{6} \to_{- 4 H_{2} O}^{100^{0} C} 2 HI O_{4} \overset{200^{0} C}{\to} I_{2} O_{5}$

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