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Chlorine reacts with hot and concentrated $N a O H$ and produces compounds $(X)$ and $(Y)$ . Compound $(X)$ gives white precipitate with silver nitrate solution. The average bond order between $C l$ and $O$ atoms in $(Y)$ is

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answer is 2.

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Detailed Solution

$3 C l_{2} + \underset{H o t & c o n c .}{6 N a O H} \overset{}{\to} \underset{(X)}{5 N a C l} + \underset{(Y)}{N a C l O_{3}} + 3 H_{2} O$

$\underset{(X)}{N a C l} + A g N O_{3} \overset{}{\to} \underset{(w h i t e p p t)}{A g C l} + N a N O_{3}$

Average bond order between $C l$ and $O$ atom in $N a C l O_{3} = \frac{5}{3} = 1.67$

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